(x^2-4x+4)/(x^2+4x-12)*(2x+12)/(6x^2-13x+2)

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Solution for (x^2-4x+4)/(x^2+4x-12)*(2x+12)/(6x^2-13x+2) equation:


D( x )

6*x^2-(13*x)+2 = 0

x^2+4*x-12 = 0

6*x^2-(13*x)+2 = 0

6*x^2-(13*x)+2 = 0

6*x^2-13*x+2 = 0

6*x^2-13*x+2 = 0

DELTA = (-13)^2-(2*4*6)

DELTA = 121

DELTA > 0

x = (121^(1/2)+13)/(2*6) or x = (13-121^(1/2))/(2*6)

x = 2 or x = 1/6

x^2+4*x-12 = 0

x^2+4*x-12 = 0

x^2+4*x-12 = 0

DELTA = 4^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-4)/(1*2) or x = (-64^(1/2)-4)/(1*2)

x = 2 or x = -6

x in (-oo:-6) U (-6:1/6) U (1/6:2) U (2:+oo)

(((x^2-(4*x)+4)/(x^2+4*x-12))*(2*x+12))/(6*x^2-(13*x)+2) = 0

(((x^2-4*x+4)/(x^2+4*x-12))*(2*x+12))/(6*x^2-13*x+2) = 0

((x^2-4*x+4)*(2*x+12))/((x^2+4*x-12)*(6*x^2-13*x+2)) = 0

x^2-4*x+4 = 0

x^2-4*x+4 = 0

DELTA = (-4)^2-(1*4*4)

DELTA = 0

x = 4/(1*2)

x = 2 or x = 2

(x-2)^2 = 0

x^2+4*x-12 = 0

x^2+4*x-12 = 0

DELTA = 4^2-(-12*1*4)

DELTA = 64

DELTA > 0

x = (64^(1/2)-4)/(1*2) or x = (-64^(1/2)-4)/(1*2)

x = 2 or x = -6

(x+6)*(x-2) = 0

6*x^2-13*x+2 = 0

6*x^2-13*x+2 = 0

DELTA = (-13)^2-(2*4*6)

DELTA = 121

DELTA > 0

x = (121^(1/2)+13)/(2*6) or x = (13-121^(1/2))/(2*6)

x = 2 or x = 1/6

(x-1/6)*(x-2) = 0

((x-2)^2*(2*x+12))/((x+6)*(x-2)^2*(x-1/6)) = 0

( 2*x+12 )

2*x+12 = 0 // - 12

2*x = -12 // : 2

x = -12/2

x = -6

( x-2 )

x-2 = 0 // + 2

x = 2

x in { -6}

x in { 2}

x belongs to the empty set

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